this post was submitted on 08 May 2024
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solution
With partial fractions:1/(n + n²) = 1/(n(n+1)) = A/n + B/(n+1)
A(n+1) + Bn = 1
n = 0 gives A = 1, n = -1 gives B = -1
1/(n+n²) = 1/n - 1/(n+1)
Σ (n = 1 to ∞) 1/(n+n²) = Σ (n = 1 to ∞) 1/n - Σ (n = 1 to ∞) 1/(n+1)
= Σ (n = 1 to ∞) 1/n - Σ (n = 2 to ∞) 1/n
= 1/1 + Σ (n = 2 to ∞) 1/n - Σ (n = 2 to ∞) 1/n
= 1
Guessing this is the standard solution