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Finding an instance that blocks least and is least blocked (lemmy.one)

submitted 1 year ago by Kurt@lemmy.one to c/asklemmy@lemmy.ml

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Is there a way to shop around for a Lemmy instance based on how many instances are blocking it and how many instances it's blocking? For example, I noticed that the lemmygrad.ml instance is relatively popular, but it seems like a lot of other instances block it. It also blocks a bunch of other instances. So, if there are any communities on there that might be relevant to me then I would be missing out. I guess I could just create an account on a walled instance, but I would prefer not to keep creating accounts. I'd like to just find one instance that maximizes my access. Is the answer to just run my own instance?

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[–] knighthawk0811@lemmy.one 3 points 1 year ago (2 children)

can an instance have only 1 community for support and then have no content of its own? I believe that many already do (or near to it). This would likely be the recipe for blocking the least and being blocked the least.

[–] Kurt@lemmy.one 1 points 1 year ago (1 children)

What about an instance with only one user?

[–] knighthawk0811@lemmy.one 1 points 1 year ago (1 children)

self instance? sure, but that's not one you can join persay

[–] Kurt@lemmy.one 1 points 1 year ago (1 children)

Ah, but I can if it's mine, right? I'm going to give it a shot.

[–] knighthawk0811@lemmy.one 4 points 1 year ago

loads of people are making their own and doing pretty much this. I'm planning on giving it a try sometime over the summer. should be a fun project that I can actually keep using for a while. maybe even make my own notes or something.

I might explore options to make private content just for myself

[–] Swyperider@lemmy.ml 1 points 1 year ago (1 children)

Instance owners would block that kind of instance based on the activity of its users instead.

[–] knighthawk0811@lemmy.one 1 points 1 year ago

they certainly can do that. I wonder if we'll get to that point where there are SPAM instances that every other instance will need to deal with