this post was submitted on 27 Nov 2023
18 points (84.6% liked)
Asklemmy
43757 readers
1163 users here now
A loosely moderated place to ask open-ended questions
Search asklemmy ๐
If your post meets the following criteria, it's welcome here!
- Open-ended question
- Not offensive: at this point, we do not have the bandwidth to moderate overtly political discussions. Assume best intent and be excellent to each other.
- Not regarding using or support for Lemmy: context, see the list of support communities and tools for finding communities below
- Not ad nauseam inducing: please make sure it is a question that would be new to most members
- An actual topic of discussion
Looking for support?
Looking for a community?
- Lemmyverse: community search
- sub.rehab: maps old subreddits to fediverse options, marks official as such
- !lemmy411@lemmy.ca: a community for finding communities
~Icon~ ~by~ ~@Double_A@discuss.tchncs.de~
founded 5 years ago
MODERATORS
you are viewing a single comment's thread
view the rest of the comments
view the rest of the comments
This is kind of a weirdly phrased question.
Mathematically, THE argument of the sine function is the angle in question. One definition of sine, using the sides of a right triangle, is the ratio of the opposite leg to the hypotenuse of said triangle: sin(theta)=opposite/hypotenuse.
Edit: it occurred to me that maybe what you're asking is how to compute the angle, theta, for which sin(theta) = a certain ratio of opposite/hypotenuse. There is an inverse sine function (often called arcsin) that does just that. Arcsin(opp/hyp)=theta. That's the case where it would make sense to take the side lengths as arguments.