this post was submitted on 17 Jul 2023
421 points (88.6% liked)
Programmer Humor
32464 readers
150 users here now
Post funny things about programming here! (Or just rant about your favourite programming language.)
Rules:
- Posts must be relevant to programming, programmers, or computer science.
- No NSFW content.
- Jokes must be in good taste. No hate speech, bigotry, etc.
founded 5 years ago
MODERATORS
you are viewing a single comment's thread
view the rest of the comments
view the rest of the comments
I don't know much about PW security but would a passphrase of common words not be more susceptible to dictionary attacks?
The idea is that entropy is measured with possible words instead of possible characters. It turns out 7 7-bit ascii characters have less entropy than 4 14-bit equivalent words (that is, the 16,384 most common ones). And that's in the ideal case it's a totally random 7 characters.
Every attack is technically a dictionary attack here, but it doesn't help enough because the password to a computer is still 30 characters long. To a human it seems a lot easier than ")f1:.{yJCzNv]@R=S K$~=", though.
PS. Turning /dev/random output into 7-bit ascii characters is surprisingly involved in Haskell. C would have been easier. This was the world's slowest ninja edit.
Thanks for the explanation, I remember the explanation in https://xkcd.com/936/ but wasn't sure how that held up for different attack methods.