this post was submitted on 08 Jun 2024
1209 points (98.3% liked)
memes
10440 readers
2600 users here now
Community rules
1. Be civil
No trolling, bigotry or other insulting / annoying behaviour
2. No politics
This is non-politics community. For political memes please go to !politicalmemes@lemmy.world
3. No recent reposts
Check for reposts when posting a meme, you can only repost after 1 month
4. No bots
No bots without the express approval of the mods or the admins
5. No Spam/Ads
No advertisements or spam. This is an instance rule and the only way to live.
Sister communities
- !tenforward@lemmy.world : Star Trek memes, chat and shitposts
- !lemmyshitpost@lemmy.world : Lemmy Shitposts, anything and everything goes.
- !linuxmemes@lemmy.world : Linux themed memes
- !comicstrips@lemmy.world : for those who love comic stories.
founded 1 year ago
MODERATORS
you are viewing a single comment's thread
view the rest of the comments
view the rest of the comments
The question is from project management certificate exam
My kid showed me a test question from a junior high math test about construction a building in 12 months with x number of workers, how many workers do they need to hire if they want it done in 6 months.
So I guess if you answer that question "wrong" youd be smart, and if you answer it right, management. Even a junior high student mocked it...
Well, if T is total time to build, D is the time that can be distributed equally among any number of workers, and C is constant, indivisible time extra time that goes along with construction, and X is the number of workers, then:
T - C = D / X
so, since T is 12 and 6 is half of 12, then:
T/2 - C = D/X * 1/2
or
T/2 - C = D/2X where X > 0, C = 0, T=12, and D = (T - C) / X
which is both the answer it's looking for (twice as many workers) and the correct answer (it depends on at least two things we don't know), while assuming what they're assuming, which is C = 0
(Stupid ass junior high math problems piss me off, junior high is a traumatic experience)
Well, arguably still "incorrect" in real world terms since it fails to have an adjustment for divisibility of D as a function of how many people. If theoretically a task is "perfectly divisible" at two people and halves the time, it will not be the case that a million people will cause it to happen in one millionth of the time. Improvement by expressly pointing out "C" and declaring your assumption of zero for math to work. Also assumption than for any increment of X, the time impact is equal.
In math this is pedantic, but it sure impact project planning in very disastrous ways, and business people love to assume C is zero, any change to X is linear and with linear impact, and make embarrassingly bad calls as a result.
yup, but that answer was based entirely on the assumptions present in the question. D is all divisible work, and C is everything else, because that's literally all you can assume to make the math work. D has to therefore be 12 months worth of divisible work minus C. C could very well be 12 months of work, meaning D is zero and adding more workers won't matter.