this post was submitted on 14 Sep 2023
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[–] 4kki@feddit.de 8 points 1 year ago (2 children)
[–] theyoyomaster@lemmy.world 10 points 1 year ago

So as a pilot and a hobbyist photographer I wasn't able to come up with a definitive answer from google. Virtually all results end up on schlieren photography which is something I've been aware of, but only in controlled settings. I do think it might be the answer here though. The ELI5 answer is that it takes super fast shutter speeds which require a lot of light. This photo is conveniently lit by the sun behind the F-18 which means it is basically a pseudo schlieren setup. Super bright source behind the image but blocked just enough to not bloom it out allowed for the super fast shockwave to be captured. If anyone knows more please feel free to chime in, I would love to learn more on this.

[–] FooBarrington@lemmy.world 4 points 1 year ago (1 children)

What we see is light being refracted in "weird" ways. It's similar to the way light above a very hot surface, like asphalt on a hot sunny day, appears to be warped.

Everything has a refractive index, meaning a number that determines how much light is warped. Air is usually very evenly distributed, so you don't see much (or any) warping. But the airplane moves so fast that it pushes the air in front of it to the side, which means around the airplane the air is denser. The refractive index of air changes with density. This makes the light appear so warped :)

Fun fact, the sonic boom also comes from the air being pushed to the side. Behind the airplane there is a pocket without air (or with very little). The higher density around the airplane is not stable, gases want to be evenly distributed. This makes the air crash violently into itself as it fills the pocket, which produces the sound! This also explains why you hear the sonic boom everywhere along the path of the airplane, and not just where it breaks the sound barrier.

[–] Faresh@lemmy.ml 2 points 1 year ago (1 children)

But then that means what we see has nothing to do with breaking the speed of sound. So is the only relation between the distortion and breaking the sound barrier the fact that one needs to be quite fast for both?

[–] FooBarrington@lemmy.world 3 points 1 year ago

Yes, in the sense that you already get a weaker version of this effect below the sound barrier. You don't need to break it to see them.