this post was submitted on 19 Nov 2024
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[–] peanuts4life@lemmy.blahaj.zone 11 points 11 hours ago (1 children)

Maybe my math is wrong but: The Earth's radius is about 6,371 kilometers. With this large radius and a 24-hour rotation period, the centripetal acceleration at the equator is only about 0.034 m/s². This is tiny compared to Earth's gravitational acceleration of 9.8 m/s². So the centripetal effect is only about 0.3% of gravity's effect.

[–] perviouslyiner@lemmy.world 1 points 9 hours ago* (last edited 9 hours ago) (1 children)

40,075,000m circumference / 86,400s = 463m/s?

[–] peanuts4life@lemmy.blahaj.zone 5 points 8 hours ago* (last edited 8 hours ago)

Yes, that is the speed you're going, then the acceleration you experience due to the change in direction as the earths surface revolves about an axis is a = v²/r. R being the radius of the earth. This gets us our small acceleration value.

You do experience this small acceleration as a very small reduction in weight. You actually weigh more at the poles than the equator. You don't feel the velocity at all, as the whole planet is moving with you.