this post was submitted on 28 Aug 2024
476 points (98.4% liked)
196
16501 readers
3111 users here now
Be sure to follow the rule before you head out.
Rule: You must post before you leave.
founded 1 year ago
MODERATORS
you are viewing a single comment's thread
view the rest of the comments
view the rest of the comments
~~They each move at a constant speed, but the distance between them doesn't increase at a constant pace. See my other comment.~~
Edit: I am dumb, and looked at the wrong number.
I'm trying to apply the most simple math possible and it seems to add up.
After one second, their distance is √(5² + 1²) = ~5.1 ft
After two seconds, their distance is √(10² + 2²) = ~10.2 ft
After three seconds, it's √(15² + 3²) = ~15.3 ft
As speed is the rate of change of distance over time, you can see it's a constant 5.1 ft/s. You're free to point out any error, but I don't think you need anything more than Pythagoras' theorem.
The question specifically asks for their seperation speed at 5s to ignore any initial change in their speed as they first need to accelerate, I'd assume.
Ah sorry, I'm tired and made a mistake. I quickly made a spreadsheet (because keeping track of numbers is hard), and I was looking at the wrong column in the sheet. My bad!
You were tired so you made a spreadsheet to calculate the differential equation quiz from a meme?
Yes, compared to doing the calculations in my head lol
I work in mysterious ways