That's true but (at least here in Sweden and among my friends and classmates) I think most people read at least occasionally. Personally, however I'm in the +10 category by a long shot
Hjalamanger
I doubt the accuracy of this map. I have never seen a dominos in Sweden and I've seen a few dunkin donuts so the map is, at least not fully accurate. Also didn't McDonald's shut down in Russia?
Could you please post a source for this map?
Don't you guys not Kung fu fight on boats in the ocean??? I thought everyone did that!
nice game! although I feel like some of the setups in tumbling ballistic are impossible to beat, although there just random. Anyways, here's my very messy code:
// Arguments:
let {x_position, altitude, angle, userStore} = arguments[0];
let target_angle = 0
let x_thrust = 0
///////////////
// Side slip //
///////////////
let half = 159
let ms = 400
let target_speed = ((half - x_position) / half) * ms
if (altitude < 150 || target_speed < 0.1 * ms)
target_speed = 0
if (!("px" in userStore)) {
userStore.px = x_position
}
let dx = userStore.px - x_position
userStore.px = x_position
let xs = dx * 60 + target_speed
let axs = xs > 0 ? xs : -xs
target_angle = axs < 90 ? xs : 90 * (xs / axs)
x_thrust = (axs / 90) * (target_angle > 0 ? target_angle : -target_angle) * 1
if (x_thrust > 1) {
x_thrust = 1
}
x_thrust = x_thrust * ((target_angle > 0 ? target_angle : -target_angle) / 90)
let atas = altitude < 150 ? altitude / 150 : 1
target_angle *= atas
let ad = target_angle - angle
let aad = ad > 0 ? ad : -ad
let aa = angle > 0 ? angle : -angle
let xtc90 = altitude < 500 ? (altitude / 500) * 30 : 30
if (aa > 90 + xtc90 || aad > 45 || altitude < 200) {
x_thrust = 0
}
//////////////
// Altitude //
//////////////
if (!("da" in userStore)) {
userStore.da = 0;
}
if (!("pa" in userStore)) {
userStore.pa = altitude;
}
userStore.da = userStore.pa - altitude
userStore.pa = altitude
let as = userStore.da * 60
let tas = altitude / 1.35 + 0.2
let thrust = 0
if (as > tas) {
thrust = 1
}
let acb = 200 + (as > 250 ? 100 : 0)
let angle_cutoff = altitude < acb ? 89 * (as / 200) : 35
if (angle_cutoff > 89) angle_cutoff = 89
if ((angle > 0 ? angle : -angle) > angle_cutoff) {
thrust = 0
}
thrust += x_thrust
if (thrust > 1) {
thrust = 1
}
//////////////
// Rotation //
//////////////
if (!("dr" in userStore)) {
userStore.dr = 0;
}
if (!("pr" in userStore)) {
userStore.pr = angle;
}
userStore.dr = userStore.pr - angle
userStore.pr = angle
let rs = userStore.dr * 60
let ars = rs > 0 ? rs : -rs
let rsrtm = 0.02
let rt = (-(angle - target_angle) / 360) * 10 + rs * rsrtm
let ardmc = 50
if (ars < 30) ardmc = 0
let rd = angle - target_angle
let ard = (rd > 0 ? rs : -rd) + rs * ardmc
let ard180_1 = 180 - (angle > 0 ? angle : -angle)
let ard180_2 = 180 - (target_angle > 0 ? target_angle : -target_angle)
let ard180 = ard180_1 + ard180_2 - rs * ardmc
if (((target_angle > 0) != (angle > 0)) && ard180 < ard && false) {
rt -= rs * rsrtm
rt = -rt
}
if (rt > 1) rt = 1;
else if (rt < -1) rt = -1;
// Return:
return { rotThrust:rt, aftThrust:thrust,userStore:userStore };
What in the whole dam world is linex forte stabilni slozeni 2?
That's extremely noticeable with left handed people trying to draw on whiteboards
I don't know, but I would've think so. Part of the reason is that almost no one actually learns to read this stuff fluently without using the key and going letter by letter. So getting any significant sample of people to test it on would probably be hard
I can't read (or write) it without the key, however I'm quite fast if I get to do it. I have thought of trying to learn it completely, mainly to see how hard it would be and what I'd learn (apart from, you know, learning brädgårdschiffer) from learning a "new" alfabet. I'd be interested to see how I view it in comparison to regular Latin script. I speak somewhere between 2 and 4 languages depending on how you count and I've found every new one interesting and insightful to learn so it would be fun to see if learning to read a new script fluently would be anywhere near as insightful. Ultimately I'd like to learn Korean or Chinese but that be a major challenge and take a lot of time (also, I could probably not squeeze it in to my formal education with the path I'm going to take so I'd have to do it in my free time)
Yeah, sure you can just substitute out the letters or write them out as is. And thanks for the image, i always get problems with images proxyed through ddg and then my instance
Does one two one representations of the Latin alfabet count? In such case I'd mention a cipher used in Sweden called "brädgårdschiffer". Here is "hej på dig!" written using brädgårdschiffer with my very sloppy writing on my phone:
It's decrypted by matching up the shape and amount of dots with the letters in the key below. You look at the edges around the letters and the dots above that square.
I do however think that this chiffer probably exists outside of Sweden under some other name and other letters included (note that W and Q aren't included in the key. They aren't really used for in Swedish, apart from loans from other languages)
Whilst of course unlikely it might be possible if you accept that the women is around 34 year's old. Then she gave birth to her daughter at 15 and that's not common but also not impossible (I've meet a kid to a mother who's fifteen years older then her kid)
But in the end this is probably just made up, so what gives?
Lego figures would love this
Can I get a conversation table?