Could be easily made 50% space saving by only iffin all odds and return even on else. Maybe one if before to handle overflow to avoid wrong even if over the last if.

[–] Deebster@programming.dev 41 points 10 months ago

Well yeah, if you allow cheating!

[–] bjorney@lemmy.ca 18 points 10 months ago* (last edited 10 months ago) (1 children)

Yeah but then ALL even numbers would be slow to compute because you would have to chain through every odd before you know that 2 is even.

Depends on the expected distribution of input values

[–] coloredgrayscale@programming.dev 1 points 10 months ago

Heuristic: keep it until 512, afterwards powers of 2, and numbers like 1000, 2000,.., 10000, 20000,... (regex: [0-9]000+)